How do you write #y=3/4x+1# in standard form?

1 Answer
Dec 7, 2016

#3x-4y=-4#

Explanation:

Equations in standard form are written: ax + by = c, where #a# is a positive integer (natural/counting number) and #b# and #c# are integers.

To write the equation, which is given in slope-intercept form, in standard form, you must first subtract #3/4x# from both sides of the equation: #-3/4 x + y = 1#. Because #a# (ax + by = c) must be a positive integer, multiply each value in the equation by #-4#: #-4* (-3/4x + y =1) -> 3x-4y=-4.# This is the final equation in standard form.

#-a/b# in your standard form equation should be equal to the slope of the line. Thus the slope is equal to #3/4#.