How do you write y=3/4x+1 in standard form?

1 Answer
Dec 7, 2016

3x-4y=-4

Explanation:

Equations in standard form are written: ax + by = c, where a is a positive integer (natural/counting number) and b and c are integers.

To write the equation, which is given in slope-intercept form, in standard form, you must first subtract 3/4x from both sides of the equation: -3/4 x + y = 1. Because a (ax + by = c) must be a positive integer, multiply each value in the equation by -4: -4* (-3/4x + y =1) -> 3x-4y=-4. This is the final equation in standard form.

-a/b in your standard form equation should be equal to the slope of the line. Thus the slope is equal to 3/4.