How do you solve #x^(2/3)+15=24#?

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Answer 1 · 2016-12-09T00:19:43

#x=+-27#

Given:

#x^(2/3)+15 = 24#

Subtract #15# from both sides to get:

#x^(2/3) = 9#

Cube both sides to get:

#x^2 = 729#

Take the square root of both sides, allowing for both positive and negative square roots to get:

#x = +-27#

Assuming that we are dealing purely with Real numbers, both of these solutions are solutions of the original equation.