What is the equation of the line that passes through #(1, -5)# and #(-3,7)#?

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Answer 1 · 2016-12-10T15:49:50

Here's the explanation.

Let, the coordinates, #(1,-5)# be #(x_1,y_1)# & #(-3,7)# be #(x_2,y_2)#, where the slope of the line is,

#m=(y_2-y_1)/(x_2-x_1)#.

So, #m=(7+5)/(-3-1)=-3#.

Now, the equation of the line is:

#y-y_1=m(x-x_1)#.

So put the values & keep the #x# & the #y# intact & you can get the equation.

Hope it Helps.