What is the angular momentum of a rod with a mass of # 8 kg# and length of #4 m# that is spinning around its center at #15 Hz#?

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Answer 1 · 2016-12-15T10:56:05

The angular momentum is #=80pi=251.3kgm^2s^(-1)#

The angular momentum is

#L=Iomega#

The moment of inertia of a rod is #I=1/12ml^2#

#I=1/12*8*4=8/3kgm^2#

The angular velocity is #omega=15*2pi rads^(-1)#

So,

#L=8/3*30pi kgm^2s^(-1)=80pi kgm^2s^(-1)#