Question

How do you solve and find the value of `sin(sin^-1(1/2))`?

Answer 1

`sin(sin^(-1)(1/2))=1/2`

Explanation:

`sin^(-1)(1/2)` means an angle `theta` so that `sintheta=1/2`

As we have `sin(pi/6)=1/2`, `sin^(-1)(1/2)=pi/6`

and `sin(sin^(-1)(1/2))=sin(pi/6)=1/2`