How do you solve #\sqrt { - 5x - 9} = 11#?
1 Answer
Dec 19, 2016
#x=-26#
Explanation:
Given -
#sqrt(-5x-9)=11#
To eliminate the root, square both sides
#(sqrt(-5x-9))^2=11^2#
#-5x-9=121#
Add
#-5x-9+9=121+9#
#-5xcancel(-9) cancel(+9)=130#
Divide both sides by#-5#
#(-5x)/(-5)=130/(-5)#
#(cancel(-5)x)/cancel(-5)=130/(-5)#
#x=-26#
