Question

A miner finds a small mineral fragment with a volume of `5.74` `cm^3` and a mass of `14.4` `g`. What is its density?

Answer 1

`rho="mass"/"volume"~=2.5*g*cm^-3`

Explanation:

`rho=(14.4*g)/(5.74*g*cm^-3)=??*g*cm^-3`