What is the equation of the line, in slope-intercept form, that goes through the point #(-6,4)# with #m=-1/2#?

1 Answer
Dec 20, 2016

#y=-1/2x+1#

Explanation:

To start, slope-intercept form is #y=mx+b#
where #m# is the slope and #b# is the y-intercept.

However, when just given a point, (-6,4) ,and the slope, we need to use another form called point slope form.

which is #y-y_1=m(x-x_1)#

Here, #y_1 = 4, and x_1# = #-6# (from the point given in the question),
and #m# is #-1/2#

Our equation is now: #" "y-4=-1/2(x+6)#

Next, we need to distribute the #-1/2(x+6)#

This yields #-1/2x-3#

With this, Our equation is now #y-4=-1/2x-3#

Our last step is to add 4 to both sides. (to isolate #y#)

We now get #y=-1/2x+1# and this is your answer in slope-intercept form.

Hope this helps!