How do you solve for x in #y=(e^x-e^-x)/6 #?

1 Answer
Dec 21, 2016

#x = sinh^-1(3y)#

Explanation:

#3y = (e^x - e^-x)/2#

It has been found that #sinhx = (e^x- e^-x)/2#, where #y = sinhx# is the hyperbolic sine function.

Thus,

#3y = sinhx#

#sinh^-1(3y) = x#

I'm not entirely sure that this is the answer you want. If you want something else, write a note and I'll change the answer accordingly.

Hopefully this helps!