How do you find the area enclosed by the x-axis and the given curve y=(6/x) for x between -4 & -2?

1 Answer
Dec 23, 2016

Area = int_-4^-2(6/x)dx = 6 ln (1/2)

Explanation:

Simply integrate the function y=(6/x) between the bounds given, -4 and -2.

int_-4^-2(6/x)dx = 6 int_-4^-2 1/x \ dx

" " =6 [ln |x|]_-4^-2

" " = 6 { ln |-2| - ln |-4 }
" " = 6 { ln 2 - ln 4 }
" " = 6 { ln (2/4) }
" " = 6 ln (1/2)