Given #sectheta=5# and #tantheta=2sqrt6#, how do you find #cot(90^circ-theta)#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Shwetank Mauria Dec 25, 2016 #cot(90^@-theta)=2sqrt6# Explanation: As #cot(90^@-theta)=tantheta# #cot(90^@-theta)=2sqrt6# Note there is no need to use #sectheta=5# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2446 views around the world You can reuse this answer Creative Commons License