How do you find the max or minimum of #f(x)=3x^2#?

1 Answer
Dec 27, 2016

Differentiate the function and equate the differential to 0, then solve for x.

Explanation:

#dy/dx 3x^2 = 6x#

Let #6x = 0#

#x = 0/6 = 0#

The critical point (max or min) is at #x = 0#. To find the y coordinate of this point substitute #x = 0# into the original equation. #y = 3(0)^2 = 0#
Thus the coordinates of the min/max point are #0,0#.