How do you differentiate f(t)=1/4(t^4+8)? Calculus Basic Differentiation Rules Power Rule 1 Answer kumail ยท Monzur R. Dec 27, 2016 dy/dt 1/4 (t^4 + 8) = 1/4 dy/dt t^4 + 8 = 1/4 (4t^3) +0 = t^3 Explanation: Use the power rule to differentiate terms. Power rule: If y =ax^n Then dy/dx=nax^(n-1) Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of y =1/sqrt(x)? How do you find the derivative of y =4/sqrt(x)? How do you find the derivative of y =sqrt(2x)? How do you find the derivative of y =sqrt(3x)? How do you find the derivative of y =sqrt(x)? How do you find the derivative of y =sqrt(x) using the definition of derivative? How do you find the derivative of y =sqrt(3x+1)? How do you find the derivative of y =sqrt(9-x)? How do you find the derivative of y =sqrt(x-1)? See all questions in Power Rule Impact of this question 4100 views around the world You can reuse this answer Creative Commons License