Question

Question #81fe9

Answer 1

(see below)

Explanation:

Consider the relationship between decreasing powers of any number.

If we let `n` be such a number then we see that (for example):
`color(white)("XXX")n^4 = n^5 div n`

`color(white)("XXX")n^3 = n^4 div n`

`color(white)("XXX")n^2 = n^3 div n`

`color(white)("XXX")n^1 = n^2 div n`

if we continue...
`color(white)("XXX")n^0 = n^1 div n` (n.b. this is just `ndivn=1`)
and
`color(white)("XXX")n^(-1) = n^0 div n` (that is `1divn = 1/n`; the reciprocal of `n`)