Question #0b46c

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Answer 1 · 2017-01-03T23:09:13

Here's how I would do it.

Step 1. Draw a 10-carbon (decane) chain.

$decane$ $"decane"$

Step 2. Number the carbons from left to right.

Attach an isopropyl group to carbon 4.

$4-isopropyldecane$ $"4-isopropyldecane"$

Step 3. Attach a sec-butyl group to carbon 5.

$4-isopropyl-5-sec-butyldecane$ $"4-isopropyl-5-sec-butyldecane"$

And you have the structure.