Question

How do you solve `-8(z+6)<-8z-7`?

Answer 1

Move all of the constants to one side of the equation with algebraic operations just as with and equality. Change the inequality direction only when multiplying or dividing by a negative number.

Explanation:

1) Perform the indicated multiplications to get all of the factors.

−8 (z+6) < −8z − 7 ; -8z – 48 < -8z - 7

2) Add 8z to both sides and the inequality is shown to be true.
-48 < -7