Question

How do you integrate `1/(2x+1)`?

Answer 1

`int (dx)/(2x+1) = 1/2 ln abs (2x+1)+C`

Explanation:

`int (dx)/(2x+1) = 1/2 int (d(2x+1))/(2x+1) = 1/2 ln abs (2x+1)+C`