How do you solve by factoring and using the principle of zero products: #64v^2=36#?

1 Answer
sente
Jan 9, 2017

#v in {-3/4, 3/4}#

Explanation:

The zero product principle states that if #ab = 0# then #a=0# or #b=0#. Together with the special product #a^2-b^2 = (a+b)(a-b)#, we can solve for #v#:

#64v^2 = 36#

#=> 64v^2 - 36 = 0#

#=> (8v)^2 - 6^2 = 0#

#=> (8v+6)(8v-6) = 0#

#=> 8v+6 = 0 or 8v-6 = 0#

#=> 8v = -6 or 8v = 6#

#=> v = -6/8 or v = 6/8#

#:. v in {-3/4, 3/4}#

Related questions
See all questions in Zero Product Principle
Impact of this question
1747 views around the world
You can reuse this answer
Creative Commons License