Question

How do you differentiate `1 / ln(x)`?

Answer 1

`d/(dx) (1/(lnx)) = -1/(xln(x)^2)`

Explanation:

Using the chain rule: if `y=ln(x)` and `u=1/y` then:

`(du)/(dx) = (du)/(dy)*(dy)/(dx)`

So:

`d/(dx) (1/(lnx)) = -1/(ln(x)^2)*1/x= -1/(xln(x)^2)`