How do you solve by factoring #n^2+ 2n -24 =0#?

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Answer 1 · 2017-01-10T14:56:49

See full process for solving the problem below:

You need to play with multiples of 24 (1x24, 2x12, 3x8, 4x6) for the constant term which add to #2# for the #n# term to factor:

#(n + 6)(n - 4) = 0#

We can now solve each term for #0#.

Solution 1)

#n + 6 = 0#

#n + 6 - color(red)(6) = 0 - color(red)(6)#

#n + 0 = -6#

#n = -6#

Solution 2)

#n - 4 = 0#

#n - 4 + color(red)(4) = 0 + color(red)(4)#

#n - 0 = 4#

#n = 4#

The solution is #n = -6# and #n = 4#