A solid disk, spinning counter-clockwise, has a mass of #6 kg# and a radius of #8/5 m#. If a point on the edge of the disk is moving at #4/3 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-01-12T10:45:06

The angular momentum is #=40.24kgms^-1#
The angular velocity is #=5.24rads^-1#

The angular velocity is

#omega=v/r#

where,

#v=4/3ms^(-1)#

#r=8/5m#

So,

#omega=(4/3)/(8/5)*2pi=5/3pi=5.24 rads^-1#

The angular momentum is #L=Iomega#

For a solid disc, #I=(mr^2)/2#

So, #I=6*(8/5)^2/2=192/25=7.68kgm^2#

#L=5.24*7.68=40.24kgms^(-1)#