How do you differentiate the following parametric equation: # x(t)=-te^t-2t, y(t)= 3t^3-4t #?

Question

1611 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-14T07:10:51

The answer is #=-((e^t+te^t+2))/((9t^2-4))#

We need

#(uv)'=u'v-uv'#

#(e^x)'=e^x#

#(x^n)'=nx^(n-1)#

#x(t)=-te^t-2t#

#y(t)=3t^3-4t#

#dx/dt=-(e^t+te^t+2)#

#dy/dt=9t^2-4#

#dy/dx=(dy/dt)/(dx/dt)=-((e^t+te^t+2))/((9t^2-4))#