How do you simplify #(2 - 4i)(8 + 3i)#?
1 Answer
Jan 14, 2017
Explanation:
distribute the brackets using, for example, the FOIL method.
#rArr(2-4i)(8+3i)=16+6i-32i-12i^2#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(2/2)|)))#
#rArr16-26i-12i^2=16-26i+12#
#=28-26i#
