How do you find the product of #(2m-3)(m+4)#?

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Answer 1 · 2017-01-16T02:43:01

See full process explanation below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2m) - color(red)(3))(color(blue)(m) + color(blue)(4))# becomes:

#(color(red)(2m) xx color(blue)(m)) + (color(red)(2m) xx color(blue)(4)) - (color(red)(3) xx color(blue)(m)) - (color(red)(3) xx color(blue)(4))#

#2m^2 + 8m - 3m - 12#

We can now combine like terms:

#2m^2 + (8 - 3)m - 12#

#2m^2 + 5m - 12#