How do you graph #y=-6/x# using asymptotes, intercepts, end behavior?
1 Answer
Jan 16, 2017
No intercepts, since, as x/y
Explanation:
This is xy=-6 representing the rectangular hyperbola, with center at
O and asymptotes as the axes of coordinates xy =0.
graph{(y+6/x)(x+.001)(x-.01)(y)=0 [-20, 20, -10, 10]}