How do you use implicit differentiation to find dy/dx given #2^sqrt(xy)=x#?
2 Answers
Explanation:
Differentiate both members of the equation with respect to
Substitute
Solving for
Now note that:
and so:
Substituting in the expression of
You can also first make
Obtaining naturally the same result.
x and y > 0.
Explanation:
graph{x-2^sqrt(xy)=0x^2 [-39.94, 39.94, -19.96, 19.98]} To make the function real,
Using logarithmic differentiation,