Question

What is the vertex of # y= –x^2 +x – 12?

Answer 1

`(1/2, -47/4)`

Explanation:

`y=-x^2+x-12` => complete the square to convert to vertex form:
`y=-(x^2-x)-12`
`y=-(x^2-x+1/4)-12+1/4`
`y=-(x - 1/2)^2-47/4`
=> in the vertex form of`(x-h)^2+k` where`(h, k)` is the vertex:
so in this case the vertex is:
`(1/2, -47/4)`