How do you solve #2(x-4)<=2+3(x-6)#?

1 Answer
Jim G.
Jan 21, 2017

#x>=8#

Explanation:

The first step is to distribute the brackets on both sides of the inequality.

#rArr2x-8<=2+3x-18#

Next, collect terms in x to one side and numeric values on the other side.

subtract 2x from both sides.

#cancel(2x)cancel(-2x)-8<=2+3x-2x-18#

#rArr-8<=x-16#

Isolate x on the right side by adding 16 to both sides.

#-8+16<=xcancel(-16)cancel(+16)#

#rArr8<=xrArrx>=8#

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