A graduated cylinder contains 225 mL of water. What is the new water level affer 30.2 g of silver metal with a density of 10.5 g/mL is submerged in the water?

1 Answer
anor277
Jan 21, 2017

Well, we work out the water displaced by the silver........

Explanation:

Well, we work out the water displaced by the silver........by calculating the volume of the silver nugget using the density.

#"Density"(rho)# #=# #"Mass"/"Volume"#

Thus #"Volume"="Mass"/rho#

#=# #(30.2*g)/(10.5*g*mL^-1)# #~=# #3*mL#.

This is consistent dimensionally, because #cancelg/(cancelg*mL^-1)=1/(1/(mL^-1))=mL# as required.

So the volume will be approx. #228*mL#

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