How do you solve for E in #V-E+F=2#?

Question

6661 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-21T22:15:00

See the entire solution process below:

First, subtract #color(red)(V)# and #color(blue)(F)# from each side of the equation to isolate the #E# term while keeping the equation balanced:

#V - E + F - color(red)(V) - color(blue)(F) = 2 - color(red)(V) - color(blue)(F)#

#V - color(red)(V) - E + F - color(blue)(F) = 2 - color(red)(V) - color(blue)(F)#

#0 - E + 0 = 2 - V - F#

#-E = 2 - V - F#

Now, multiply each side of the equation by #color(red)(-1)# to solve for #E# while keeping the equation balanced:

#color(red)(-1) xx -E = color(red)(-1)(2 - V - F)#

#E = -2 + V + F#