Question

How do you find the amplitude and period of `y=3sin(2/3theta)`?

Answer 1

See answer below

Explanation:

The amplitude is

`y_(max)=3`

The period is

`T=(2pi)/(2/3)=3pi`

graph{3sin(2/3x) [-0.056, 11.04, -2.703, 2.85]}