Question

How do you find the amplitude and period of `y=1/2cos3theta`?

Answer 1

Amplitude: `1/2`

Period: `T = (2 pi )/ 3`

Explanation:

You can see that the function has amplitude `1/2` by inspection, ie it is `y = color(red)(1/2) cos 3 theta` so it oscillates as `y in [-1/2, 1/2]`.

In terms of the period, a sine function that is in form `y = sin omega theta` has period `T = (2 pi )/ omega`. In this case, it has period `T = (2 pi )/ 3`.