A charge of $8 C$ $8 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $17 J$ $17 J$ to $1 J$ $1 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-01-24T20:09:53

$- 2$ $-2$ V

$d U = Q d V$ $dU = Q dV$

$d V = \frac{d U}{Q}$ $dV = (dU)/Q$

$= \frac{1 - 17}{8} = - 2$ $= (1-17)/8 = -2$ V

A charge of 8C8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 17J17 J to 1J1 J, what is the voltage between points A and B?