Question #5b7cb
1 Answer
Jan 25, 2017
Explanation:
We know that in such interactions heat is gained by one and heat is lost is by the other.
Also that the heat gained/lost is given by
#DeltaQ=mst# ,
where#m,s and t# are the mass, specific heat and rise or gain in temperature of the object;
and
#Delta Q_"lost"=Delta Q_"gained"#
Let
Heat gained by water
Equating (1) and (2) we get
Multiplying both sides by