Question

Question #6fd74

Answer 1

`angleRQP=45^@`
`angleSPR=50^@`
`anglePSR=80^@`

Explanation:

Given that `SP=SR, and angleSRP=50^@`,
`=> DeltaSRP` is isoceles, `=> angleSPR=angleSRP=50^@`
`=>anglePSR=180-50-50=80^@`

As `PQ` is parallel to `SR, => angleRPQ=angleSRP=50^@`
`=> angleRQP=180-85-50=45^@`