How do you find the amplitude and period of y=1/2sin2thetay=12sin2θ?

1 Answer
Jan 25, 2017

"amplitude " =1/2," period" =piamplitude =12, period=π

Explanation:

The standard form of the color(blue)"sine function"sine function is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))

"where amplitude "=|a|," period "=(2pi)/b

"phase shift "=-c/b" and vertical shift " =d

"here "a=1/2,b=2,c=0,d=0

rArr"amplitude "=|1/2|=1/2," period " =(2pi)/2=pi