Question

How do you find the amplitude and period of `y=1/2sin2theta`?

Answer 1

`"amplitude " =1/2," period" =pi`

Explanation:

The standard form of the `color(blue)"sine function"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))`

`"where amplitude "=|a|," period "=(2pi)/b`

`"phase shift "=-c/b" and vertical shift " =d`

`"here "a=1/2,b=2,c=0,d=0`

`rArr"amplitude "=|1/2|=1/2," period " =(2pi)/2=pi`