Two opposite sides of a parallelogram each have a length of #12 #. If one corner of the parallelogram has an angle of #(5 pi)/12 # and the parallelogram's area is #162 #, how long are the other two sides?

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Answer 1 · 2017-01-27T07:53:07

#13.92#

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The area of parallelogram is #=bcsinA# where #b and c# are the length of sides with angle #A# between of them.

Let say #x# is a length of other sides.

#x*12*sin(5/12pi)=162#

#x*12*0.97=162#

#x=162/11.64#

#x=13.92#