What is the axis of symmetry and vertex for the graph y= -3/5x^2 + 6x -1?

1 Answer
Jan 28, 2017

the axis of symmetry is x=5
the vertex is V(5;14)

Explanation:

Since from the general equation y=ax^2+bx+c. the formulas for the axis of symmetry and the vertex are respectively:

x=-b/(2a)

and

V(-b/(2a); (4ac-b^2)/(4a)),

you would get:

x=-cancel6^3/(cancel2*(-3/5))=cancel3*5/cancel3=5

and

V(5;(4*(-3/5)* (-1)-6^2)/(4*(-3/5)))

V(5;(12/5-36)/(-12/5))

V(5;(-168/cancel5)/(-12/cancel5))

V(5;14)

graph{y=-3/5x^2+6x-1 [-5, 10, -5, 20]}