How do you find the product of #(7y - 8)^2#?

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Answer 1 · 2017-01-29T00:32:51

See the entire solution process below:

First, we can rewrite this expression as:

#(7y - 8)(7y - 8)#

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(7y) - color(red)(8))(color(blue)(7y) - color(blue)(8))# becomes:

#(color(red)(7y) xx color(blue)(7y)) - (color(red)(7y) xx color(blue)(8)) - (color(red)(8) xx color(blue)(7y)) + (color(red)(8) xx color(blue)(8))#

#49y^2 - 56y - 56y + 64#

We can now combine like terms:

#49y^2 + (-56 - 56)y + 64#

#49y^2 - 112y + 64#