A cylinder has inner and outer radii of #2 cm# and #12 cm#, respectively, and a mass of #2 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #24 Hz# to #18 Hz#, by how much does its angular momentum change?

Question

941 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-29T12:53:22

The answer is #=0.558 kg ms^-1#

The angular momentum is #L=Iomega#

The change in angular momentum is

#DeltaL=IDelta omega#

For a cylinder, #I=(m(r_1^2+r_2^2))/2#

So, #I=2*(0.02^2+0.12^2)/2=0.0148kgm^2#

#Delta omega=(24-18)*2pi =12pi rads^-1#

#DeltaL=0.0148*12pi=0.558kgms^(-1)#