How do you solve and write the following in interval notation: #x^2 + 6 <2x#?

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Answer 1 · 2017-01-29T14:48:28

The solution #S={O/}#

Let's rewrite the equation

#x^2-2x+6<0#

We complete the squares

#x^2-2x+1+5<0#

#(x-1)^2+5<0#

Let #f(x)=(x-1)^2+5#

So,

#AA x in RR, f(x)>0#

There is no solution to the inequality