How do you differentiate # f(x)= sqrt((xe^x+4)^3 # using the chain rule.?

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Answer 1 · 2017-01-30T20:12:29

#f'(x)=3/2e^x(1+x)(sqrt(xe^x+4))#

#f(x)=sqrt((xe^x+4)^3)=((xe^x+4)^(3))^(1/2))=(xe^x+4)^(3/2)#

#[f(x)]^n=n[f(x)]^(n-1)xxf'(x)#

#d/dxuv=uv'+vu'#

#f'(x)=3/2(xe^x+4)^(1/2)xx(e^x+xe^x)=#

#3/2e^x(1+x)sqrt(xe^x+4)#