How do you factor the expression #c^3-6c^2-16c#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Tony B Feb 1, 2017 #c(c-8)(c+2)# Explanation: Each term has a #c# in it so step one is to factor that out. #c(c^2-6c-16)# Notice that #2xx(-8)=-16# and that #2-8=-6# So we have: #c(c-8)(c+2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1187 views around the world You can reuse this answer Creative Commons License