A cylinder has inner and outer radii of #2 cm# and #4 cm#, respectively, and a mass of #15 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #4 Hz# to #7 Hz#, by how much does its angular momentum change?

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Answer 1 · 2017-02-01T14:39:37

The answer is #=0.283kgms^(-1)#

The angular momentum is #L=Iomega#

#DeltaL=IDelta omega#

For a cylinder, #I=m(r_1^2+r_2^2)/2#

So, #I=15*(0.02^2+0.04^2)/2=0.015kgm^2#

#Delta omega=(7-4)*2pi=6pi rads^-1#

#DeltaL=0.015*6pi=0.283kgms^(-1)#