Question

Question #aba1e

Answer 1

Balanced equation of the reaction

`NH_4NO_3" "->" "N_2O(g)+2H_2O`

`" "1"mol"" "" "" "" "1"mol"`

`" ""=80g"" "" "" "" ""=22400mL"" ""at STP"`

`" ""x" "g=?"" "" "" "" "" 250mL"" ""at STP"`

So

`x/80=250/22400`

`=>x=(80xx250)/22400g~~0.89g`