How do you find the product #(b-7)(b+3)#?

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Answer 1 · 2017-02-03T14:14:21

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(b) - color(red)(7))(color(blue)(b) + color(blue)(3))# becomes:

#(color(red)(b) xx color(blue)(b)) + (color(red)(b) xx color(blue)(3)) - (color(red)(7) xx color(blue)(b)) - (color(red)(7) xx color(blue)(3))#

#b^2 + 3b - 7b - 21#

We can now combine like terms:

#b^2 + (3 - 7)b - 21#

#b^2 - 4b - 21#