How do you factor #8u^3-24u^2v+18uv^2#?
2 Answers
Feb 5, 2017
The answer is
Explanation:
We need
Therefore,
Feb 5, 2017
Explanation:
Given:
#8u^3-24u^2v+18uv^2#
Note that all of the terms are divisible by
Then the remaining quadratic is a perfect square trinomial, being of the form:
#A^2-2AB+B^2 = (A-B)^2#
with
#8u^3-24u^2v+18uv^2 = 2u(4u^2-12uv+9v^2)#
#color(white)(8u^3-24u^2v+18uv^2) = 2u((2u)^2-2(2u)(3v)+(3v)^2)#
#color(white)(8u^3-24u^2v+18uv^2) = 2u(2u-3v)^2#