How do you graph #y=(x^2-9)/(2x^2+1)# using asymptotes, intercepts, end behavior?
1 Answer
Feb 8, 2017
y-intercept ( x = 0 ) :
Horizontal asymptote :
Vertical asymptote :
Explanation:
graph{((x^2-9)/(2x^2+1)-y)(y-1/2)x=0 [-10, 10, -5, 5]}
y-intercept ( x = 0 ) :
x-intercept ( y = 0 ) :
By actual division,
So, y = 1/2 is the asymptote.
As
Inversely, x =+-sqrt((y=9)/(1-2y)=+-sqrt((1+9/y)/(1/y-2)) to 0, as y to -oo#.
So,