What are the intercepts of #-31x-4y=9#?

1 Answer
Feb 9, 2017

To find the intercepts you need to set the other variable to #0# and solve for the intercept variable you are looking for:

Solution for y-intercept - set #x = 0# and solve for #y#:

#(-31 xx 0) - 4y = 9#

#0 - 4y = 9#

#-4y = 9#

#(-4y)/color(red)(-4) = 9/color(red)(-4)#

#(color(red)(cancel(color(black)(-4)))y)/cancel(color(red)(-4)) = -9/4#

#y = -9/4#; y-intercept is #-9/4# or #(0. -9/4)#

Solution for x-intercept - set #y = 0# and solve for #x#:

#-31x - (4 xx 0) = 9#

#-31x - 0 = 9#

#-31x = 9#

#(-31x)/color(red)(-31) = 9/color(red)(-31)#

#(color(red)(cancel(color(black)(-31)))x)/cancel(color(red)(-31)) = -9/31#

#x = -9/31#; x-intercept is #-9/31# or #(-9/31, 0)#