How do you solve #s+1/6<=2/3#?

Question

1078 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-09T22:10:15

See the entire solution process below:

First, subtract #color(red)(1/6)# from each side of the inequality to solve for #s# while keeping the inequality balanced:

#s + 1/6 - color(red)(1/6) <= 2/3 - color(red)(1/6)#

#s + 0 <= 2/3 - 1/6#

Multiply #2/3# by the appropriate form of #1# to put both fractions over a common denominator so they can be added together:

#s <= (2/2 xx 2/3) - 1/6#

#s <= 4/6 - 1/6#

#s <= 3/6#

#s <= 1/2#